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Mathematics 13 Online
OpenStudy (tmagloire1):

AP CALCULUS AB URGENT HELP http://prntscr.com/ayifl0

OpenStudy (tmagloire1):

Please help anyone?

OpenStudy (xguardians):

Let me finish the rest of my opened questions then I can help you out! Need some practice for my AP exam this upcoming week.

OpenStudy (tmagloire1):

ok thanks

OpenStudy (xguardians):

So, first we know that g(x) is the integral of the graph f(x), therefore, we know that the graph we are being shown is the first derivative of g(x).

OpenStudy (tmagloire1):

Yeah!

OpenStudy (xguardians):

Do you know how to tell when it is increasing and concave down?

OpenStudy (tmagloire1):

Yeah its increasing so its concave down.

OpenStudy (xguardians):

If the g(x) is increasing, you simply look at f(x) for any values that are positive. To find if it is concave up or down, you must take a look at the second derivative (or the slope of f(x)). Positive slopes are concave up, negative slopes are concave down.

OpenStudy (xguardians):

Therefore, I believe between the values of [-3,0] fulfill these requirements.

OpenStudy (tmagloire1):

So that interval would be in an open interval?

OpenStudy (tmagloire1):

? @xGuardians

OpenStudy (xguardians):

What do you mean?

OpenStudy (xguardians):

Oops, I made a quick mistake. I thought you said concave up my bad.

OpenStudy (xguardians):

It should be between 0 and 2 that fulfill these requirements. Since the graph is increasing, yet concave down as it approaches 0. My apologies.

OpenStudy (tmagloire1):

Okay, thank you for the help!

OpenStudy (xguardians):

How did you just assume f(t) = (x+3)?

OpenStudy (tmagloire1):

So after I re integrate I would get an interval of -3, 0?

OpenStudy (tmagloire1):

because you have to take the differentiate the integral?

OpenStudy (tmagloire1):

ohh ok

OpenStudy (tmagloire1):

so i got x+3 for the integral

OpenStudy (tmagloire1):

and 0 for the second derivative

OpenStudy (tmagloire1):

-1/6 (-6+x)^2 (3+x) ?

OpenStudy (tmagloire1):

second derivative would be 3-x

OpenStudy (zarkon):

you should use xGuardians's idea. You are working too hard. This is a 5-10 second problem.

OpenStudy (tmagloire1):

id still like to continue @Loser66 's way since i started

OpenStudy (tmagloire1):

lol wait so on the problem where do i go from getting the second derivative

OpenStudy (tmagloire1):

im p sure the answer is -3,0 like @xGuardians said though

OpenStudy (xguardians):

You should just be able to look at the graph, this problem is not too difficult. However, you may follow Loser66 to further understand it if you can't look at it and instantly see. Let me know if you need a more detailed explanation.

OpenStudy (xguardians):

@Loser66 , no problem. @tmagloire1, do you need any more assistance?

OpenStudy (zarkon):

on -3 to 0 the function is concave up...don't you want concave down?

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