College Algebra Questions?
1. First, write the value(s) that make the denominator(s) zero. Then solve the equation.
(x-6/4x)+3=x+7/x

2. Solve the equation.
2/y+3-8/y-3=12/y^2-9

3. Solve the absolute value inequality. Other than ∅, use interval notation to express the solution set and graph the solution set on a number line
2 + [1 - x/2] ≥ 5

Question

College Algebra Questions? 
1. First, write the value(s) that make the denominator(s) zero. Then solve the equation. 
 (x-6/4x)+3=x+7/x

2. Solve the equation. 
 2/y+3-8/y-3=12/y^2-9

3. Solve the absolute value inequality. Other than ∅, use interval notation to express the solution set and graph the solution set on a number line 
 2 + [1 - x/2] ≥ 5

jtug6 · Answer

So then the first thing you'd want to do is set the denominators of your fractions equal to zero. I'd recommend putting parenthesis for the numerator/denominator but i'll assume the (4x+3) and (x) are the denominators for #1

jtug6 · Answer

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