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Mathematics 24 Online
OpenStudy (sushi121212):

Please help me on #22 and #24!

OpenStudy (sushi121212):

OpenStudy (anonymous):

\[\frac{ AM }{ BM }=\tan 60,AM=BM \tan 60=3\tan 60=?\]

OpenStudy (sushi121212):

Where did the 3 come from?

OpenStudy (sushi121212):

Is AM 3?

OpenStudy (sushi121212):

Am is \[3\sqrt{3}\]?

OpenStudy (anonymous):

BC=6 BM=half of BC

OpenStudy (sushi121212):

BM = 3

OpenStudy (anonymous):

AM is correct.

OpenStudy (sushi121212):

So AO is \[2\sqrt{3}\]

OpenStudy (sushi121212):

And OM is \[\sqrt{3}\]

OpenStudy (anonymous):

I think AO is half of AM

OpenStudy (anonymous):

AO is perpendicular on the plane ABC

OpenStudy (anonymous):

correction VO not AO

OpenStudy (anonymous):

\[VO \perp ~on~ plane~ ABC\]

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