Question

Check

Answer 1

all that are true about the graph of y > x2 + 4x + 4

Answer 2

The parabola opens up.
The line of symmetry is y = -2.
The vertex is at (-2, 0).
The parabola is dashed.

Answer 3

Hold on and I'll try to help you:)

Answer 4

suree thanks<3

Answer 5

Okay, the sign of the coefficient of the x² term is positive, so the parabola opens upward. The line of symmetry is a vertical line, so it will be an x-value, not y. The vertex is (- 2, ) and the parabola is dashed and shaded inside.

Answer 6

Make Sense??

Answer 7

Yes it is shaded, I think i'm right :3

Answer 8

There's also this way:

1.) The sign of the coefficient of the x² term is positive, so the parabola opens upward. The line of symmetry is a vertical line, so it will be an x-value, not y. The vertex is (- 2, ) and the parabola is dashed and shaded inside.

2.) The dashed parabola means that the curve itself is not included, so, on the number line, an open circle means that the point is not included.

3.) The only exponents in a quadratic are 1 and 2, so y < x² - 5 is the quadratic inequality.

4.) y < x² - 4x + 3
x² - 4x + 3 > y
x² - 4x + 3 > 0
x² - 4x > - 3
x² - 4x + 4 > - 3 + 4
(x + 2)² > 1
x + 1 > √1
x + 1 > ± 1
x > - 1 ± 1

If x > - 1 + 1,
x > 0

If x > - 1 - 1,
x > - 2

Since (1, 0) and (2, - 1) are in the domain, they are points in the solution set.
....

Answer 9

Lol i'll write that down too ;)

Answer 10

lol.. okay ;)