What is the distance between the points (1, –6) and (–5, 2)? Round your answer to the nearest tenth. A. 5.6 units B. 7.2 units C. 9.0 units D. 10.0 units
A right?
@ShadowLegendX
@PillowFace750
We could use the Distance Formula, have you seen it before?
Yes I have seen it before
We could do that, or make a triangle
A triangle?
Have you heard of the Pythagorean Theorem?
Ohhhhhh yeah I know what that is.
\[a ^{2}+b ^{2}=c ^{2}\]
How do you think we might be able to solve this, using the Pythagorean Theorem?
Well, I know how to solve it once I plug in the numbers but I am not sure right now where to put the numbers, but I know we have to plug them in
I'll give you a hint. Here are the two points on a graph http://prntscr.com/b0o4bo
That red line is the distance between the two points, but could it also be?
what could it also be
I have to go soon, and you're offline, so I'll provide you with the proper information
Sorry I am online, my internet was acting up
The distance between the two points, is the hypotenuse of a triangle http://prnt.sc/b0o3zf
Ohhhhhhhhh
They both meet at -5, 6
I mean -5, -6 right?
yeah
You see how it works though, right?
Okay, so is that what I plug in for the therom? And yeah
Use the Pythagorean Theorem, yeah. You get the sides by counting the units on each side. Then use them to calculate the hypotenuse
Ohhhhh so it would be C, 9.0 units!
How did you get that?
I counted the units on each side to caluculate the hypotenuse
Oh wait, ugh I am mixing this up sorry, wrong answer
You can count for these |dw:1462474609145:dw| but not these |dw:1462474622346:dw|
Has to be a straight line, with an undefined slope, or a slope of 0
Aka, it goes straight up and down on the y axis, or straight left and right on the x axis
I gtg, use 8^2 + 6^2 = c^2 With c being your answer
Okay, thanks :)
I was just about to do that lol
Ah, I got 100 squared. I think I am doing this all wrong
Wait, unless I fix it so it equals D
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