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What answer do you think it is?
Not quite. \(\Huge{(n^{2})^{9}} \rightarrow n^{18}\) Since we mulitply the exponents and get a positive it would be \(\Large{n^{18}}\)... In order to get \(\LARGE{\frac{1}{n^{18}}}\) we would have to have the exponents be opposites so one would have to be a positive and the other a negative....which would that be?
Correct ^^
np ^^
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