Question

Please help will fan and medal!


Audra counted change collected for a class fundraiser. Audra wrote the equation 0.10x+0.25y=5.30 to represent the situation. What did she define as the variable x?

value of a dime
value of a quarter
number of dimes collected
number of quarters collected

Answer 1

@RhondaSommer @xGuardians

Answer 2

@Anaise

Answer 3

@AloneS

Answer 4

I'm so confused

Answer 5

https://www.symbolab.com/solver/functions-calculator/0.10x%2B0.25y%3D5.30/?origin=button

Answer 6

I don't get it?

Answer 7

they gave you a calculator, which is useless in this equation

Answer 8

for real

Answer 9

@RhondaSommer So can you help?

Answer 10

It's 2:00 am I'm super sleepy but I have to finish the couple of questions that are left.

Answer 11

0.10x+0.25 \[quarters~are~~\frac{25}{100}=0.25\]\[dimes~are~~~~~~\frac{10}
{100}=0.10\]
so if x is multiplied by (0.10) what is (x) going to be?

Answer 12

0.10 dollar=10 cents=value of one dime
so x is number of dimes.

Answer 13

dimes

Answer 14

perfect :D

Answer 15

Value of a dime*

Answer 16

One more please?

Answer 17

sure :D

Answer 18

Wait, is it number of dimes collected or value of a dime?

Answer 19

I think it's number of dimes collected..?

Answer 20

number of dimes. because it is being multiplied by the value of a dime

Answer 21

Ok

Answer 22

Carissa works as a babysitter during her summer vacation. She gets paid one rate for daytime hours and a higher rate for nighttime hours. One week, she worked 12 daytime hours and 4 nighttime hours and earned $120. The next week, she earned $60 for a total of 4 daytime hours and 3 nighttime hours. Let x represent the hourly daytime rate and y represent her hourly nighttime rate.

12x+4y=120
4x+3y=60

What is the solution to the system of equations?
(3,4)
(4, 12)
(6, 12)
(10, 30)

Answer 23

hey @xGuardians

Answer 24

Care to help?

Answer 25

@RhondaSommer Hello?

Answer 26

OH MY GOODNESS. BE FRICKIN PATIENT

Answer 27

IM SO SORRY!

Answer 28

multiply second eq. by 3 and subtract from eq 1.

Answer 29

ok
\[No. 1~~~~12x+4y=120\]\[No. 2~~~~4x+3y=60\]\[multiply~No.2~equation~by~-3\]\[(4x+3y=60)-3\]\[wich~becomes~-12x-9y=-180\]\[combine No.1~and~modified~No.2~divide~and~both~sides~by~-5\]\[~~~12x+4y=~~~120\]\[-12x-9x=-180\]\[---------\]\[~~~~~~~~~~\frac{-5y}{-5}=~\frac{-60}{-5}\]\[~~~~~~~~~~~~~~~~~y=~~12\]\[place~12~in~for~(y)~in~the~origonal~No.2~equation\]\[4x+3(12)=60\]\[4x+36=60\]\[subtract~36~from~both~sides~and~divide~both~!sides~by~4\]\[\frac{4x}{4}~~~~~~~=\frac{24}{4}\]\[x~~~~~~~~~~~=6\]

Answer 30

(6,12)?

Answer 31

Yes!

Answer 32

so if \[(x,y)\]and\[x=6~y=12\]\[(6,12)\]

Answer 33

Thanks so much!

Answer 34

How can I repay you?

Answer 35

yeah :D sorry it took a while to write all that in. :D

Answer 36

I already fan and medaled anything else?

Answer 37

uh...that's it...maybe right a testimonial for me?

Answer 38

Already did I think..?

Answer 39

if you hover over my name you can right a testimonial for them...

Answer 40

I did

Answer 41

Let me see my grade

Answer 42

90% thanks so much

Answer 43

:D yeah no problem :D