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Mathematics 13 Online
OpenStudy (ninjaslice):

Hi guys, I need help with my work, I am attaching a screenshot for you, if you could explain to me how, what the answer is, and how you got to it .... that would be VERY appreciated.

OpenStudy (ninjaslice):

OpenStudy (ninjaslice):

WIll medal if someone can help me .

jimthompson5910 (jim_thompson5910):

x^2-6x-9 does NOT factor to (x-3)^2 it should be x^2-6x+9 = (x-3)^2

jimthompson5910 (jim_thompson5910):

I suggest FOILing out (x-3)*(x-3) or using the box method to confirm that it does equal x^2-6x+9

OpenStudy (mathmale):

Try re-ordering the terms in the second line of this "solution," to reflect what Jim has just said. You are "completing the square."

OpenStudy (ninjaslice):

Ok, and one more question, its my last one. If you could Verify my answer

jimthompson5910 (jim_thompson5910):

The part above where you circled is cut off

OpenStudy (mathmale):

First of all, make certain you understand what a "zero" is in this context: It's an x-value at which the function equals zero, that is, y=0. So, if you wish to find the zeros of this function, set the function= to zero and solve for x. Please show your work here.

OpenStudy (mathmale):

You could use "completing the square" again, or you could use the quadratic formula.

OpenStudy (ninjaslice):

Thank you. If i have any further questions ABOUT those 2 i will let you know.

OpenStudy (mathmale):

I should have mentioned this earlier, but factoring the given expression might prove to be the easiest approach of all. Good luck; hope to work with you again.

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