Hi guys, I need help with my work, I am attaching a screenshot for you, if you could explain to me how, what the answer is, and how you got to it .... that would be VERY appreciated.
WIll medal if someone can help me .
x^2-6x-9 does NOT factor to (x-3)^2 it should be x^2-6x+9 = (x-3)^2
I suggest FOILing out (x-3)*(x-3) or using the box method to confirm that it does equal x^2-6x+9
Try re-ordering the terms in the second line of this "solution," to reflect what Jim has just said. You are "completing the square."
Ok, and one more question, its my last one. If you could Verify my answer
The part above where you circled is cut off
First of all, make certain you understand what a "zero" is in this context: It's an x-value at which the function equals zero, that is, y=0. So, if you wish to find the zeros of this function, set the function= to zero and solve for x. Please show your work here.
You could use "completing the square" again, or you could use the quadratic formula.
Thank you. If i have any further questions ABOUT those 2 i will let you know.
I should have mentioned this earlier, but factoring the given expression might prove to be the easiest approach of all. Good luck; hope to work with you again.
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