Question

The quadratic equation x^2+a=0 where a>0, ______ has at least one real number solution

A. Always B. Sometimes C.Never

Answer 1

I was thinking C, is that right?

Answer 2

if you add -a to both sides you get
x^2 + a - a = 0 -a
or
x^2 = -a

they tell you a>0, so you know -a is a negative number
now take the square root
x= sqr(-a)

is that a real number ?

Answer 3

No, so is it C?

Answer 4

yes, for a>0 you always get two imaginary answers

Answer 5

@phi Thank you! I've been trying to figure it out for ages