Complete the equation for the linear function whose graph contains the point (−1, 2) and has a slope of 0.9. y =____x + ____ i imagine it would start like y = 0.9x + ____ maybe y = 0.9x + 2 ??
You are very close! The slope is as you say 0.9. It means that if you increase x by 1, you increase y by 0.9. However, if y = 0.9x + 2, then what happens if you plug in x = -1. You do not get 2, but rather y = 0.9*(-1) + 2 = 1.1.
Therefore, + 2 cannot be right. You should have gotten 2, since the line was supposed to go through (-1,2)
that makes sense, but then how do i figure out what goes in that space?
what number*
Ok, good. Well, what if we say that the right number is a, so that y = 0.9*x + a You know that y = 2 at x = -1
If you solve for a, then you get the constant term :)
okay let me do that, and see what i get
the slope intercept form of the line is \[y = mx + b\] m = slope which you know and b = y- intercept so your line is \[y = 0.9x + b\] to find the value of b, use the point x = -1 and y = 2 substitute them and solve for b
Could not agree more, campbell_st :)
hmm okay i got 2 = 0.9 x -1 + 2.9
correct
so now you know b... and have the equation of the line
can you help with another one @SfunnSneffanS ?
Sure :)
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