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What is the line of symmetry of the parabola
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y=x^2+6x-9?
I'm kind of lost so i organized this way. a=\(x^{2}\) b=6 c=-9 the next this i have to find the formula \(\frac{ -6 }{ 2(a) }\) but i'm confused on this, what do i put for "a".
Oh wait or is that \(\frac{ =6 }{ 2(1) }\) since x=1
HI!!
\(a\neq x^2\) because \(a\) is a number in this case it is \(a=1\)
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Oh okay thank you! I was actually thinking of that, but i had doubt /:
also \(x\) is a variable, it can be anything, it is not \(x=1\) but you have the right idea \[-\frac{b}{2a}=-\frac{6}{2\times 1}\]
Oh so basically i was right, and the symmetry line would be x=-3 Thanks misty<3
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