Question

A student is asked to calculate the Pythagorean Triples for the number 13 using the identity (x2 − y2)2 + (2xy)2 = (x2 + y2)2. The student's steps are shown below.

Step 1: 13 = 72 − 62; therefore, x = 7 and y = 6

Step 2: (72 − 62)2 + (2 ∙ 7 ∙ 6)2 = (72 + 62)2

Step 3: (a − b)2 + (84)2 = (49 + 36)2

Step 4: (13)2 + (84)2 = (c)2

Step 5: The Pythagorean Triples are 13, 84, and 85.

In Steps 3 and 4, what are the values of a, b, and c, respectively?

14, 12, 84
49, 12, 84
49, 36, 85
13, 84, 85

Answer 1

the 2nd one

Answer 2

Solve 6x3 − 11x2 − 4x + 4 = 0 by factoring.

Answer 3

@TheBrainzzzzz