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Groundwater 12 Online
OpenStudy (csubero):

can anyone help me please https://gyazo.com/3f511ecd55b9a92c7a44c0f5ee0a8e84

OpenStudy (csubero):

@latinC

OpenStudy (csubero):

dude

OpenStudy (latinc):

what do you have so far DUDE!

OpenStudy (csubero):

what do you mean

OpenStudy (latinc):

I read your math question, but what part of the question do you need help with

OpenStudy (csubero):

like I dont get it what does it want me to do??

OpenStudy (latinc):

(A- part of the question) its asking for the probability of drawing an almond cookie on the first attempt

OpenStudy (csubero):

WAIITI

OpenStudy (csubero):

NOOO WRONG QUESTIOn

OpenStudy (latinc):

all the possible possibilities of arranging the three toys

OpenStudy (latinc):

@csubero you still here

OpenStudy (volleyballlover55):

please come back to my question..

OpenStudy (csubero):

yea im here

OpenStudy (anonymous):

\[\frac{ \left(\begin{matrix}3 \\ 1\end{matrix}\right) }{ \left(\begin{matrix}6 \\ 1\end{matrix}\right) }*\frac{ \left(\begin{matrix}2 \\ 1\end{matrix}\right) }{ \left(\begin{matrix}5 \\ 1\end{matrix}\right) } = \frac{ 3 }{ 6 } *\frac{ 2 }{ 5 }=\frac{ 1 }{ 5 }\]

OpenStudy (anonymous):

these are two dependent happening. first focus on getting one almond out of 6 cookies, then if it's happened you will have two almond in 5 cookies . so your chance to have one almond is 40% . as the two process are dependent you have to multiply them to get the final answer.

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