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Mathematics
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Solve Trianle ABC
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pls help me
HI!!
hello
is this a bunch of different questions? do you have a calculator?
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yes i have a calculator
ok lets do the first one they all involve trig and inverse trig functions
ok
you have \(A=50^\circ, a=14\)
to find \(b\) you know \[\tan(50^\circ)=\frac{14}{b}\] since it is "opposite over adjacent" solve for \(b\) via \[b=14\times \tan(50^\circ)\]
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also, since the total degrees of the angles is \(180^\circ\) and \(A=50,C=90\) you know \(B=40\)
oh ok
\[A=50\\ B=40\\ C=90\\ a=14\\ b=16.7\] all that is left is \(c\)
you can use trig or pythagoras, either way \[c=\sqrt{14^2+16.7^2}\] or \[\sin(50)=\frac{14}{c}\] so \[c=\frac{14}{\sin(50)}\]
i got 18.2
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