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Mathematics 9 Online
OpenStudy (cntrl_alt_defeated):

Solve Trianle ABC

OpenStudy (cntrl_alt_defeated):

OpenStudy (cntrl_alt_defeated):

pls help me

OpenStudy (misty1212):

HI!!

OpenStudy (cntrl_alt_defeated):

hello

OpenStudy (misty1212):

is this a bunch of different questions? do you have a calculator?

OpenStudy (cntrl_alt_defeated):

yes i have a calculator

OpenStudy (misty1212):

ok lets do the first one they all involve trig and inverse trig functions

OpenStudy (cntrl_alt_defeated):

ok

OpenStudy (misty1212):

you have \(A=50^\circ, a=14\)

OpenStudy (misty1212):

to find \(b\) you know \[\tan(50^\circ)=\frac{14}{b}\] since it is "opposite over adjacent" solve for \(b\) via \[b=14\times \tan(50^\circ)\]

OpenStudy (misty1212):

also, since the total degrees of the angles is \(180^\circ\) and \(A=50,C=90\) you know \(B=40\)

OpenStudy (cntrl_alt_defeated):

oh ok

OpenStudy (misty1212):

\[A=50\\ B=40\\ C=90\\ a=14\\ b=16.7\] all that is left is \(c\)

OpenStudy (misty1212):

you can use trig or pythagoras, either way \[c=\sqrt{14^2+16.7^2}\] or \[\sin(50)=\frac{14}{c}\] so \[c=\frac{14}{\sin(50)}\]

OpenStudy (cntrl_alt_defeated):

i got 18.2

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