What is the value of
\[10x^2+20x+8=0 \]
I'm not sure tbh. \[\sqrt{20-4(10)(8)}\]
for discriminant the 20 need square it there inside squarroote
Didn't you a big ol' quadratic formula thread yesterday with @johnweldon1993? refer to that.
Aaaah that post @agent0smith why did u bring it up :3 plus tagging him
Tagged him cos he'd be disappointed if you took away nothing from it ;)
Ayeee dudee
The formula and steps you need are in that question
OKay,okay sothe formula is \[\sqrt{b^2-4ac}\] So i did that lready and a=10^2 b=20 c=8 and than i get lost >.>
That is NOT the quadratic formula. That is the discriminant. What does this question ask you to find?
Ugh *facepalm* What is the value of \[b^2-4ac\]c for the following equation? \[10x^2+20x+8=0 \]
Then that's kinda important to know. So what are a b and c? Then just plug them into \[\Large b^2-4ac\]
I DID
A=10 b=20 c=8 \[\sqrt{(20)-4(10)(8)}\]
Yes, correct for a, b, c. You aren't asked for that. The question asked for \[\Large b^2-4ac\]
Ugh how than?
Plug in a=10, b=20, c=8 into this \[\huge b^2-4ac\]
Ooooh so now sqare toot? \[ 20^{2}-4(10)(8)\]
I FIANLLY GOT 80!
It does not ask for a square root. Based on the question you gave.
Yeah it doesn't.TANKS AGENT0
You're welcome.
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