OpenStudy (mathmusician):

Some Calculus help Please!

1 year ago
OpenStudy (mathmusician):

Part D on questions 2 and 3.

1 year ago
OpenStudy (legomyego180):

is this college cal I?

1 year ago
OpenStudy (mathmusician):

Yes it is

1 year ago
OpenStudy (mathmusician):

@ijlal

1 year ago
OpenStudy (ijlal):

i'll have a look at it :) a moment

1 year ago
OpenStudy (mathmusician):

okay thanks

1 year ago
OpenStudy (legomyego180):

Im assuming it wants you to solve the derivative where h'(x)<0 but the a throws me for a loop.

1 year ago
OpenStudy (mathmusician):

Yes that is what it wants how do I do that

1 year ago
OpenStudy (legomyego180):

Well the derivative of h(x) is h'(x)=1- a*sin(ax) where 0 < a < 4 so you would want to set this equal to 0 > 1-a*sin(ax) and the values of a where this hold true would be your answer, however Im not sure how to do that without knowing x

1 year ago
OpenStudy (mathmusician):

Do you know @ijlal

1 year ago
OpenStudy (ijlal):

that was the same thing i was thinking @legomyego180 as for a decreasing function the derivative is set <0 as the slope starts decreasing and dy/dx in this case h'(x) is decreasing so set it up as <0 \[1-asin(ax)<0\]

1 year ago
OpenStudy (mathmusician):

Yeah so do I simplify that equation or something else?

1 year ago
OpenStudy (ijlal):

Which values of a make h(x) strictly decreasing so i guess you should set x=1 as you did in part B and C to find the relative maximum and inflection point set x to 1 so, \[1-asina<0\] \[1<asina\]

1 year ago
OpenStudy (mathmusician):

Okay thanks how about for question 3?

1 year ago
OpenStudy (ijlal):

same part D?

1 year ago
OpenStudy (mathmusician):

Yep please :)

1 year ago
OpenStudy (ijlal):

kk let me have a look at it

1 year ago
OpenStudy (mathmusician):

OKay thanks

1 year ago
OpenStudy (ijlal):

Just use the slope formula use the points x=10 and x=14 to calculate the slope

1 year ago
OpenStudy (ijlal):

|dw:1463436455545:dw|

1 year ago
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