Question

Some Calculus help Please!

Answer 1

Part D on questions 2 and 3.

Answer 2

is this college cal I?

Answer 3

Yes it is

Answer 4

@ijlal

Answer 5

i'll have a look at it :) a moment

Answer 6

okay thanks

Answer 7

Im assuming it wants you to solve the derivative where h'(x)<0 but the a throws me for a loop.

Answer 8

Yes that is what it wants how do I do that

Answer 9

Well the derivative of h(x) is
h'(x)=1- a*sin(ax) where 0 < a < 4
so you would want to set this equal to
0 > 1-a*sin(ax)
and the values of a where this hold true would be your answer, however Im not sure how to do that without knowing x

Answer 10

Do you know @ijlal

Answer 11

that was the same thing i was thinking @legomyego180 as for a decreasing function the derivative is set <0 as the slope starts decreasing and dy/dx in this case h'(x) is decreasing so set it up as <0
\[1-asin(ax)<0\]

Answer 12

Yeah so do I simplify that equation or something else?

Answer 13

Which values of a make h(x) strictly decreasing so i guess you should set x=1 as you did in part B and C to find the relative maximum and inflection point set x to 1 so,
\[1-asina<0\]
\[1<asina\]

Answer 14

Okay thanks how about for question 3?

Answer 15

same part D?

Answer 16

Yep please :)

Answer 17

kk let me have a look at it

Answer 18

OKay thanks

Answer 19

Just use the slope formula use the points x=10 and x=14 to calculate the slope