Medal: What is the area of the shaded region in the given circle in terms of pi and simplest form? Photo of circle & answer choices below.
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OpenStudy (love_333):
Circle:
OpenStudy (love_333):
\[A. (30\pi+9\sqrt{3})m ^{2}\]
OpenStudy (love_333):
\[B. (24\pi +9\sqrt{3})m^2\]
OpenStudy (love_333):
\[C. (30\pi +18\sqrt{3})m^2\]
OpenStudy (love_333):
\[D. (24\pi +18\sqrt{3})m^2\]
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OpenStudy (love_333):
@563blackghost Help?
OpenStudy (anonymous):
how you think it that you can solve it easy right ?
OpenStudy (love_333):
I honestly have no idea how to work this out.
OpenStudy (anonymous):
ok.
like a first step this sector of 60 degree angle is 1/6 part of the circle - yes ?
OpenStudy (love_333):
right.
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OpenStudy (anonymous):
so bc. the circle has a central angle of 360 degree and 60 is 1/6 part of this 360
ok.
so than you calculi area of the circle and from this result you subtract this 1/6 part of this area so you get the 5/6 part from area of the circle - yes ?
OpenStudy (anonymous):
so than you assum area of this 5/6 part of the circle with area of this triangle equilateral so will get area of shaded region - do you agree it ?