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Mathematics 13 Online
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OpenStudy (kropot72):

The sample space has 36 possible combinations of numbers. These can be set out in column form as follows: 6,6 5,6 4,6 3,6 2,6 1,6 6,5 5,5 4,5 3,5 2,5 1,5 6,4 5,4 4,4 3,4 2,4 1,4 6,3 5,3 4,3 3,3 2,3 1,3 6,2 5,2 4,2 3,2 2,2 1,2 6,1 5,1 4,1 3,1 2,1 1,1 You now need to find how many sums of five and how many sums of 9 are in the table. The required probability is then found from: \[\large \frac {sums\ of\ 5\ +\ sums\ of\ 9}{36}\]

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