Question

Calculus (Integration)

Answer 1

\[\int\limits_{}^{}\frac{ 3 }{ 1-x^2 }\]

Answer 2

What grade are you in? How old are you? @legomyego180

Answer 3

This is college calculus, 24 years old

Answer 4

if you don'r mind me asking

Answer 5

No way! You're in collage!?

Answer 6

I am only a 10th grader in highschool....

Answer 7

I thought this website was just for kids....

Answer 8

Nope, see how my question says "college" on it, that means its a college level question

Answer 9

lol there are 53+ years old users :P

Answer 10

Do you know how to do this @Nnesha ?

Answer 11

is that suppose to be `1+x^2` ??

Answer 12

d*

Answer 13

\[\int\limits_{}^{}\frac{ 3 }{ \sqrt{1-x^2} }\]

Answer 14

sorry about that

Answer 15

oh okay now make sense

Answer 16

interesting to know open study has no age base.....

Answer 17

The age base is definitely age 17 and under I think. You can tell by the questions being asked. Its all highschool math mostly.

Answer 18

this is same as \[\int\limits_{}^{}\frac{ 3 }{ \sqrt{1-x^2} }dx\]
\[\int\limits_{}^{}\frac{ 1 }{ \sqrt{1-x^2} } \cdot 3 dx\]

Answer 19

right. im setting u=1-x^2

Answer 20

But I get 2x and that just doesnt work

Answer 21

True! Lol! Hope you ace what ever assignment you got! @legomyego180

Answer 22

that should be `-2x`
but as you can that's not gonna help you to simplify right

Answer 23

see*

Answer 24

Thanks @ TOgundeji!
Hm, interesting, there must be another way...

Answer 25

invs trig functions:

Answer 26

gtg

Answer 27

Ah,
3arccos(x)+c then

Answer 28

almost

Answer 29

\[\frac{d}{dx}[3 \arccos(x)+c] = -\frac{3}{\sqrt{1-x^2}}\]