Question

How do I find the x-intercepts of y=(x+2)^2+1

Answer 1

Are you using imaginary numbers? Cause if not, there are none

Answer 2

yes @Erak i am using imaginary numbers

Answer 3

oh god i'm not the best but would turning this into standard form sound familiar?

Answer 4

\[y = x^2 + 4x +5\]quadratic formula\[\frac{ -4 \pm \sqrt{16-20} }{ 2 }\]\[\frac{ -4 }{ 2 } \pm \frac{ \sqrt{4}i }{ 2 }\]\[-2 \pm i\]

Answer 5

That's what I've learned just now, so hopefully somebody swings by to confirm

Answer 6

thank you