ln(3x+7)=1.31 (ln as in log natural)
First raise both sides by e and solve for x... e^[ln(3x+7)] = e^1.31 3x + 7 = e^1.31
I was afraid that might happen.. alright let me try to write it out
(and thank you for helping)
I got \[x\approx -1.6389\]
Ya? Hmm my value is coming out slightly different..
Subtract 7, divide 3,\[\large\rm x=\frac{e^{1.31}-7}{3}\]This is what you input? Something similar?
i got closer to-1.097
I simplified e^1.31 to 2.0834 and solved algebraically from there
Honestly my teacher isn't a stickler, I don't think I'm too far off from your answer @retirEEd
Oh wait a sec, I calculated e^1.13
Whoops
Ah :D
I got -1.0979
So I got what you did @retirEEd
Try to plug in and solve for @zebdrix equation. Personally, I think your answer is significantly different. I solved mine by graphing the original equation and seeing where it equalled 1.31.
Sorry I'm watching TV so my responses are running behind your answers.
That's fine, I'm a bit scatterbrained myself. Thanks for the help @retirEEd @zepdrix
np
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