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Mathematics 9 Online
OpenStudy (jas.2002):

What is 3 root of 72 ? A. https://static.k12.com/bank_packages/files/media/a12122a7a929ed59fc166d6db6177c09.png B. https://static.k12.com/bank_packages/files/media/20305a763363b2368858a44e6634c9b7.png C. https://static.k12.com/bank_packages/files/media/54723856009732cab24a145d1fc78a9f.png D. https://static.k12.com/bank_packages/files/media/82bac8a9359eaedf6d6ad72f55ce0ab8.png Help quick please!

OpenStudy (littlediva12459):

C.

OpenStudy (littlediva12459):

https://socratic.org/questions/what-is-the-cube-root-of-72

jimthompson5910 (jim_thompson5910):

Hint: \[\Large \sqrt[3]{72}=\sqrt[3]{8*9}\] \[\Large \sqrt[3]{72}=\sqrt[3]{2^3*9}\] \[\Large \sqrt[3]{72}=\sqrt[3]{2^3}*\sqrt[3]{9}\]

OpenStudy (jas.2002):

Can you explain why please? Just so I know you're not just guessing lol.

OpenStudy (littlediva12459):

Look at the link i provided and it shows a step by step explanation

jimthompson5910 (jim_thompson5910):

You'll use these two rules \[\Large \sqrt[n]{x*y}= \sqrt[n]{x}* \sqrt[n]{y}\] \[\Large \sqrt[n]{x^n}=x\] The second rule must have n be an odd number

OpenStudy (jas.2002):

Oh okay. Thank you both so much! I have a few more questions though.. could you help?

OpenStudy (littlediva12459):

sure

OpenStudy (jas.2002):

ok hold on lol

OpenStudy (littlediva12459):

https://www.algebra.com/services/rendering/simplifier.mpl

OpenStudy (jas.2002):

I am confused..

jimthompson5910 (jim_thompson5910):

are you sure it's 135 in the root?

OpenStudy (jas.2002):

I think so...

OpenStudy (jas.2002):

Yep it is i just checked.

OpenStudy (littlediva12459):

try this video to see if it helps you understand better

jimthompson5910 (jim_thompson5910):

Hint \[\Large \sqrt[3]{135}=\sqrt[3]{27*5}\] \[\Large \sqrt[3]{135}=\sqrt[3]{3^3*5}\] \[\Large \sqrt[3]{135}=\sqrt[3]{3^3}*\sqrt[3]{5}\]

OpenStudy (jas.2002):

I still dont get it... Tell me which one it is and then try and explain and then I will probably understand lol.

OpenStudy (littlediva12459):

https://www.youtube.com/watch?v=Ds8ijPsg26g

jimthompson5910 (jim_thompson5910):

@jas.2002 you agree that 135 = 27*5 right?

OpenStudy (jas.2002):

Yeah sorry I was gone lol

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