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OpenStudy (jellybot23):
What rectangular equation is equivalent to the polar equation r csc(theta)=8
Help pleaseeeeee
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OpenStudy (jellybot23):
@Mehek14 @aaronq ??
OpenStudy (welshfella):
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OpenStudy (welshfella):
csc
OpenStudy (welshfella):
csc theta = r / y = sqrt(x^2+ y^2) / y
csc theta = 8/r = 8 / sqrt(x^2 + y^2)
therefore
sqrt(x^2+ y^2) / y = 8 / sqrt(x^2 + y^2)
OpenStudy (jellybot23):
how did you get √x^2+y^2 ?
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OpenStudy (welshfella):
pythagoras theorem
OpenStudy (welshfella):
you can simplify the above by cross multiplying
OpenStudy (jellybot23):
Oh okay! Well, my choices are x=8, y=8, x=8y^2, and x^2+(y-4)^2=16
I am trying to cross multiply now and see if I can get it
OpenStudy (jellybot23):
I got x=8?
OpenStudy (jellybot23):
@welshfella
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OpenStudy (welshfella):
No
if you cross multiply my equation you get
x^2 + y^2= 8x
OpenStudy (jellybot23):
Oh, I got x^2+y^2 = 8y
OpenStudy (welshfella):
if you simplify one of the choices you'll see that you get the above
This choice will be the answer.
OpenStudy (welshfella):
OH sorry its 8y not 8x
OpenStudy (welshfella):
so - do you see which is the correct option?
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