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Mathematics 16 Online
OpenStudy (zappy620):

Need help understanding solving trig equations pls

OpenStudy (zappy620):

\[-2\cos(3x)=-1\]

OpenStudy (mrcoolguy):

@AloneS

OpenStudy (fdane):

dicide everythg by -2..

OpenStudy (zappy620):

\[\cos(3x)=1/2\]

OpenStudy (fdane):

now cos of what angle is 1/2?

OpenStudy (zappy620):

pi/3 right

OpenStudy (zappy620):

oh and the interval is [0,2pi)

OpenStudy (fdane):

yes, then 3x=pi/3

OpenStudy (zappy620):

so x=pi/9?

OpenStudy (fdane):

is x in [0 2pi]?

OpenStudy (zappy620):

yes

OpenStudy (fdane):

so you would have one more solution because cos(300)=cos(60)=1/2

OpenStudy (zappy620):

cos(300)?

OpenStudy (zappy620):

oh cuz 360-60 right

OpenStudy (fdane):

yes

OpenStudy (zappy620):

cos(300)=cos(60)?

OpenStudy (zappy620):

i dont understand that

OpenStudy (fdane):

use this trig relation: cos(2pi-a)=cos(a) now let a be 60 ..

OpenStudy (zappy620):

2pi-60

OpenStudy (fdane):

2*180-60=300

OpenStudy (zappy620):

oh ok

OpenStudy (zappy620):

so whats the next step?

OpenStudy (fdane):

or in radians, 5pi/3

OpenStudy (fdane):

there is no more step as you have solved for x.

OpenStudy (zappy620):

is there no other solution?

OpenStudy (fdane):

in [0 2pi]? no

OpenStudy (zappy620):

ok so do we not do anything with 5pi/3?

OpenStudy (fdane):

you have found two solutions, pi/3 and 5pi/3. period

OpenStudy (zappy620):

ok thanks so much :D

OpenStudy (fdane):

never mind. good luck with your studies!

OpenStudy (fdane):

hey, i'm sorry we did somehing wrong

OpenStudy (zappy620):

:o

OpenStudy (fdane):

I don't use any pen right now so you should have told me we were doing somethig wrong. cos(3x)=1/2 3x=pi/3 --< x=pi/9 3x=5pi/3--> x=5pi/9

OpenStudy (zappy620):

ok but i dont th ink you can use 5pi/9 cuz its in the quad where cos is negative

OpenStudy (zappy620):

im so sorry i have to go im at school rn thx for helping tho

OpenStudy (fdane):

cos(5pi/9) is negative but cos(3x) where x=5pi/9 NOT!

OpenStudy (fdane):

see you

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