Question

http://prntscr.com/b6jweu

Answer 1

Basically you have your circle equation, 16 = y^2 + x^2, and your linear equation, y = -3x. You get your linear equation by finding your first differences based on the table of values.

Answer 2

If you want to know when they intersect, let's solve the circle equation for y.

16 = y^2 + x^2
y^2 = 16 - x^2
y = sqrt(16 - x^2)

Now set that equal to your linear.

-3x = sqrt(16 - x^2)
(-3x)^2 = (sqrt(16 - x^2))^2
9x^2 = 16 - x^2
10x^2 = 16
x^2 = 1.6
x = sqrt(1.6)

That gives you a positive and negative value where they intersect.

Answer 3

Read through it and ask if you need an explanation on anything.

Answer 4

so c?

Answer 5

yeah, do you get what I did?

Answer 6

Yea the way you explained helped a lot .. can you help me on one more please?:)

Answer 7

yeah post it and I'll take a look at it