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If f(x) = x2 and g(x) = 1 2x + 3 , find g(f(-1))
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Plug in -1 into the f(x) equation
First you have to find (f-1) = \(-1^2\)
After that, the value of (f-1), you put for x in g(x)
1/2x+3
that's for g right?
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yes , 1 was over 2x+3
\(\dfrac{1}{2}x+3\) like that?
no 1 over 2x+3
\(\dfrac{1}{2x+3}\)
is that how it looks?
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yes
Alright first find f(-1) = \(-1^2\) = ?
do you get the idea that f(x) is the name of a "rule" and in this case the rule is x^2 (which means x*x) and that means: if you are old x is -1, then using the rule f(x) means do -1*-1 and that is what f(-1) is
once you know what f(-1) is (as a number) you can do g( whatever number f(-1) is) and g is a different rule.
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