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You roll a number cube twice. Find the probability of the event in fraction form. Need help with #2 and #3 1. Rolling a 4 then an even number. 1/12 2. Rolling a 3 then a 3 3. Rolling a number less than 1 and then a number less than 2
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first one is right
second one, same idea. multiply
first one you got by\[\frac{1}{6}\times \frac{1}{2}\] right?
yeah
there is no number <1
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oh right
in a cube die numbers are from 1,2,...,6
so i guess you are supposed to say "zero"
so #3 would be 0?
yes, impossible event has probability zero
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okay and what about #2? how do i find the fractions i need to multiply
What's the probability of rolling a 3 when you roll a die?
#1 is harder than number 2, if you could do 1 you should be able to do 2.
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