Mathematics
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OpenStudy (fairy733189):
Which graph shows the quadratic function y = 3x^2 - 12x + 10?
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OpenStudy (zzr0ck3r):
what is the vertex of the quadratic?
OpenStudy (fairy733189):
hang on let me put the graphs
OpenStudy (zzr0ck3r):
we probably dont need them
OpenStudy (fairy733189):
OpenStudy (zzr0ck3r):
do you know what the vertex is and how to find it?
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OpenStudy (fairy733189):
yes, I know that in order to find the vertex you have to do -b/2a
OpenStudy (zzr0ck3r):
well that will tell you the x value, so do that first
OpenStudy (fairy733189):
ok:
-(-12)/2(32) = 12/ 64 = 3/16
OpenStudy (zzr0ck3r):
where did you get 32?
OpenStudy (fairy733189):
isnt that the a value?
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OpenStudy (fairy733189):
oh sorry I thought it was 32 I just realized it was 3
OpenStudy (zzr0ck3r):
\(ax^2+bx+c\)
3x^2 - 12x + 10
OpenStudy (zzr0ck3r):
correct, 3
OpenStudy (fairy733189):
so it would be:
-(-12)/2(3) = 12/6 = 2
OpenStudy (zzr0ck3r):
ok, now plug 2 back into the function and what do you get?
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OpenStudy (fairy733189):
y = 3(2)^2 - 12(2) + 10
y = 12 - 24 + 10
y = -12 + 10
I would get y = -2
OpenStudy (zzr0ck3r):
ok so the vertex is \((2,-2)\) so which graph is it?
OpenStudy (fairy733189):
would it be graph d?
OpenStudy (zzr0ck3r):
correct
OpenStudy (fairy733189):
Thank you so much!!! Do you think you can help me with another problem?
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OpenStudy (zzr0ck3r):
sure close this and ask a new one
OpenStudy (fairy733189):
ok thanks!