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OpenStudy (sarahsmiles9000):
A field test for a new exam was given to randomly selected seniors. The exams were graded, and the sample mean and sample standard deviation were calculated. Based on the results, the exam creator claims that on the same exam, nine times out of ten, seniors will have an average score within 6% of 80%.
OpenStudy (sarahsmiles9000):
Is the confidence interval at 90%, 95%, or 99%? What is the margin of error? Calculate the confidence interval and explain what it means in terms of the situation.
OpenStudy (qwertty123):
@mathmate @ganeshie8 Help?
ganeshie8 (ganeshie8):
`nine times out of ten`
is how much confidence ?
OpenStudy (sarahsmiles9000):
90%
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ganeshie8 (ganeshie8):
Good. I have just seen your work. One sec
OpenStudy (sarahsmiles9000):
Ok. (:
ganeshie8 (ganeshie8):
Margin of error is not 6℅
OpenStudy (sarahsmiles9000):
Ugh! Is it 36%?
OpenStudy (sarahsmiles9000):
That's another answer I got but it didn't see right to me.
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ganeshie8 (ganeshie8):
Nope. Margin of error is 6% of 80℅
ganeshie8 (ganeshie8):
What is 6% of 80?
OpenStudy (sarahsmiles9000):
4.8%?
ganeshie8 (ganeshie8):
Yep
that is the margin of error here
OpenStudy (sarahsmiles9000):
Ok. What about the last part of the problem?
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ganeshie8 (ganeshie8):
As the name says, confidence interval is just an interval of form (a, b)
ganeshie8 (ganeshie8):
No
OpenStudy (sarahsmiles9000):
How would I get the correct answer?
ganeshie8 (ganeshie8):
You need to calculate the interval
OpenStudy (sarahsmiles9000):
...how
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ganeshie8 (ganeshie8):
to get the lower value subtract margin of error from the mean
ganeshie8 (ganeshie8):
80 - 4.8 = ?
OpenStudy (sarahsmiles9000):
Oh! 75.2%?
ganeshie8 (ganeshie8):
You can guess how to get the upper value
ganeshie8 (ganeshie8):
simply add the margin of error to the mean
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