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\[\int\limits_{0}^{1} (x-x)^2 dx \]
Really? This seems sort of trivial :o x-x = 0, ya?
whoops suppose to be (1-x )^2
Ah :D
sorry im kind of lagging on this site :o
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oh haha :P
ahah yesh :3
So bust out that handy power rule :D Or I guess you can u-sub if you need to.
i got 1/3 as a my final result and this book has 2/3 ?
1/3 seems right... hmm that's strange.
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the answer is 1/3 you are right the book might have some sort of misprinting issues :/
yeh
the integral you get is \[\frac{ (x-1)^3 }{ 3 }\] you can check by verifying it apply derivative |dw:1463953208061:dw|
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