Question

A quadratic equation is shown below:
x^2 - 14x + 41 = 0

Which of the following is the first correct step to write the above equation in the form (x - p)^2 = q, where p and q are integers?

Add 8 to both sides of the equation

Add 9 to both sides of the equation

Subtract 8 from both sides of the equation

Subtract 9 from both sides of the equation

Answer 1

@kky10997

Answer 2

option 1st is correct

Answer 3

but how do you figure it out?

Answer 4

very good question... as this is not a place for answers...

Answer 5

its easy

Answer 6

then can you explain?

Answer 7

its easy if you know how....

Answer 8

see (x-p)^2=q x^2 +2px+p^2 =q
now compare with x^2 -14x +41 with above

Answer 9

-2px

Answer 10

sorry -2px

Answer 11

I still dont really understand it

Answer 12

now we get p= 7
so (x-7)^2= x^2 -14x+49
so to make left hand side perter squre we add 8 both side

Answer 13

but where did you get the -2px from?

Answer 14

(x-p)^2=x^2 -2px + p2