Question

In circle A shown below, the measure of ∠BAD is 148°:


If mArc BC is 105°, what is mArc CD?

74°
148°
43°
31°

Answer 1

Is there a picture?

Answer 2

@savannaadams16

Answer 3

The arc of BCD is the same as the angle BAD.
So, since arcBC is inside of arcBCD just subtract it.
arcBCD - arcBC

Answer 4

Whats the measure of BCD?

Answer 5

It would be the same measurement as angle BAD

Answer 6

so c?

Answer 7

Yes,
ArcBAD - ArcBC = 43dgrees
148 -105 =43

Answer 8

thank you! could you help with another one?

Answer 9

Sure. :)

Answer 10

In circle A shown below, mArc BC is 61° and mArc EF is 76°:


What is m∠FDE?

30.5°
38°
76°
68.5°

Answer 11

@savannaadams16 you there?

Answer 12

Yes, just trying to find the answer myself.

Answer 13

I think its 68.5

Answer 14

I believe it would be Angle FDE = 1/2(mBC + mEF)

Answer 15

1/2(61+ 76) = 68.5

Answer 16

Do you see how I got that answer?

Answer 17

yes, thank you again

Answer 18

You're welcome. :)