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Help with Lagrange Error Bound Question: Number 8 here: http://studylib.net/doc/8468990/a-function-f-x--can-be-approximated-using-a
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is it something like \[R_n(x)\leq \frac{M}{(n+1)!}|x-a|^{n+1}\]
i think in your case \(M=1\) and \(x=1.2\) giving \[R_n(x)\leq \frac{1}{(n+1)!}|.2|^{n+1}\]
yes that's it, but when I do this:\[\frac{ 0.2^{n+1} }{ {(n+1)}! }\], I get n=4
OHHHHHH.... it says terms, not degree of polynomial. Ok got it sorry
The taylor polynomial is fourth degree but the first term is a constant f(1.2)
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btw it has been a while, so i would not bet more than $7 on that answer
making the answer 5
i believe you
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