Question

The value of y varies directly with x2, and y = 64 when x = 4.

What is the value of y when x = 6?

Answer 1

@DARTHVADER2900

Answer 2

as y varies directly with x^2 the relation is
y = kx^2 where k is the constant of variation

Answer 3

uh

Answer 4

to find the value of k plug in the given values of x and y and solve for k
here y = 64 and x = 4

Answer 5

so i multiply 60 and 4

Answer 6

no replace x and y in y = kx^2 so

64 = k * 4^2

solve for k

Answer 7

362.038671968
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Answer 8

when you have found k plug this into the relation then you do the last part of the problem.

Answer 9

362.038671968

Answer 10

@welshfella 362

Answer 11

That's right