Question

how are you supposed to convert y=(x+2)(x-3) into standard and vertex form? I got y=x^2-x-6 for standard form, but I don't think this is right because I can't convert it to vertex form.

Answer 1

looks right to me

Answer 2

how do you convert that to vertex form? It doesn't work

Answer 3

why not?

Answer 4

\(x^2-x-6= x^2-x+(1/4)-(1/4)-6\)
\(=(x-1/4)^2 -25/4\)

Answer 5

ooops!! mistake
\((x-(1/2))^2-(25/4)\)

Answer 6

got it?

Answer 7

Ohh thank you, it was queer because there was a fraction in it. That messed me up! Thanks for helping :)

Answer 8

np