Question

Given the triangle below, find sec X, tan X, and cos X in fraction form.

Answer 1

@supercalifragalisticexspeaalli I see you lurking

Answer 2

lol

Answer 3

u still need help
@whovianchick

Answer 4

yep

Answer 5

im thinking C

Answer 6

what do u think it is
@whovianchick

Answer 7

No clue lol.

Answer 8

lol try C
@whovianchick

Answer 9

ok thanks

Answer 10

mp

Answer 11

First, you have a right triangle, so we can just use the Pythagorean Theorem to find the missing side that we need.

From there, just remember your basic trig functions

\[\large sin(X) = \frac{opposite}{hypotenuse} \]
\[\large cos(X) = \frac{adjacent}{hypotenuse} \]
\[\large tan(X) = \frac{opposite}{adjacent} \]

From there, you can then note that:

\[\large sec(X) = \frac{1}{cos(X)} = \frac{hypotenuse}{adjacent} \]