Find the height h of the parallelogram. A. 12 B. 15 C. 18 D. 21 IMAGE: https://vie1160-912-pps.gradpoint.com/Resource/8766464,0/Assets/testitemimages/geometry_b/area/mc015-1.jpg
I think its either 18 or 15
Do you know the area of a parallelogram ?
yes
What is it?
the area would 180
To calculate the height h of the parallelogram we need to know its base and area. b = 18 I don't know the area of tis.. Is the area given?
oh, no i had gotten the area by multiplying 18*10 which is the other height and base and it gave my 180. I don't know how to solve for the other height tho which is supposed to be the answer to the question :/
do you by chance know how to solve it to get the other height calculated?
Is any other detail/info given?
nope that is all
see attached for a few hints
thanks for the hints @jim_thompson5910 i'll see how I can use them
still need help trying to solve it all together tho :(
let me know if you're able to find h or not
\[\Large {\color{red}{\text{Area of Triangle}}} = {\color{red}{\frac{x*h}{2}}}\] \[\Large {\color{blue}{\text{Area of Parallelogram}}} = {\color{blue}{180}}\] \[\Large \text{Area of Trapezoid} = \frac{h*(b_1+b_2)}{2}\] ---------------------------------------------------------------- In this case, \[\Large b_1 = x+12\] \[\Large b_2 = 12\] ---------------------------------------------------------------- \[\large \text{Area of Trapezoid} = {\color{red}{\text{Area of Triangle}}}+{\color{blue}{\text{Area of Parallelogram}}}\] \[\Large \text{Area of Trapezoid} = {\color{red}{\frac{x*h}{2}}}+{\color{blue}{180}}\] \[\Large \frac{h*(b_1+b_2)}{2} = {\color{red}{\frac{x*h}{2}}}+{\color{blue}{180}}\] \[\Large \frac{h*(x+12+12)}{2} = \frac{x*h}{2}+180\] \[\Large \frac{h*(x+24)}{2} = \frac{x*h}{2}+180\] \[\Large \frac{h*x+24h}{2} = \frac{x*h}{2}+180\] \[\Large \frac{h*x}{2}+\frac{24h}{2} = \frac{x*h}{2}+180\] \[\Large \frac{h*x}{2}+12h = \frac{x*h}{2}+180\] Notice after this point, we subtract the terms h*x/2 from both sides and the terms will go away. Effectively eliminating x all together. Leaving just h behind. \[\Large \frac{h*x}{2}+12h{\color{green}{-\frac{h*x}{2}}} = \frac{x*h}{2}+180{\color{green}{-\frac{h*x}{2}}}\] \[\Large 12h = 180\] so if 12h = 180 then h = ???
h=15!
yes correct
thank you very very much @jim_thompson5910 :) it would've taken me a while to get that, thank you for explaining so well.
no problem
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