@aaronq
@aaronq
\[\frac{ 6a }{ 8b } \div \frac{ 10c }{ 12d }=\frac{ 2m^2 }{ n }\]
what are you solving for?
can u check ;3
Perform the indicated operation.
but none of the variables are the same.. does a=c=n?
No
Oh provably like that \[\frac{ 9ac }{ 10db}\]
heh
ohh that makes more sense. and that is correct
Or maybe \[\frac{ 9ac }{ 10 }\]
Oh lol okay thanks ;)
wait it should be 9ad/10bc
arrrong daamn u confuse me
because \(\dfrac{(\frac{a}{b})}{(\frac{c}{d})}=\dfrac{ad}{bc}\)
Luny really -.- Oooo aaarong yesh this formula
heh
lol sure
anyway, Alone, do you understand how to manipulate the fraction?
when dividing fractions, flip what u r dividing by, then multiply...right ?
I get it now....thx
I dont knowwwww I was just staljing erica e.e Sorry ;-;
Stalking*
There are many smart users, @lunymoony
6a/8b÷10c/12d=(2m^2)/n 6a 3a --- = --- 8b 4b 10c 5c ---- = --- 12d 6d 3a --- 4b 3a 6d 9ad ----- = --- * --- = ----- 5c 4b 5c 10bc --- 6d
@ganeshie8 what is here please ? ty
@Hero
hi @AloneS
Yeah, @jhonyy9 is smart, he had a good approach, but I would have finished it by simplifying it this way instead: \(\dfrac{\dfrac{3a}{4b}\times24bd}{\dfrac{5c}{6d} \times 24bd} = \dfrac{9ad}{10bc} \)
Oh thanks ;3 I just needed this reviewed
Don't you still have to solve for a particular variable @AloneS
No. I just need that. Thanks
<<Yeah, @jhonyy9 is smart, he had a good approach >> thank you very much @Hero
What about aaron? ;3
He smart too, but math probably isn't his strong suit. Probably History or Science, both of which are mathematical in their own right, and he is quite excellent as such.
You sureay stalked him before saying that.
*surely
Don't spam, and everything I said wasn't about him.
You're the one whos continuing it.
If you say so, then I must have.
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