Question

I don't do well with word problems......at least I know how to work the fan and medal buttons :D

The length of a rectangle is 3 m less than twice the width, and the area of the rectangle is 14 m^2 Find the dimensions of the rectangle.

Answer 1

Call the width of the rectangle W.
How would you write "twice the width"?
How would you write "twice the width minus 3 meters"?
What does the problem say about "twice the width minus 3 meters"?

Answer 2

rect length=2 *width-3
area=14
l*w=14

Answer 3

Hey, @shaik0124 , let's see if we can help him get _better_ at word problems?

Answer 4

k

Answer 5

(or her. Oops)

Answer 6

in word problems please first note down all the details given in the question
so that u will be able to solve the problem very easily

Answer 7

then try to link the equations u get to find a particular value and subsitute the obtained value wherever required to reach ur final answer

Answer 8

scarlett did u get ur answer

Answer 9

no. I am not sure how the equation is suppose to be set up.
is it 3-2w=14

Answer 10

it is given that 3 less than 2 width it's like 3<2w
so 2w-3

Answer 11

so I reversed it?

Answer 12

Can you walk me through how to solve this?

Answer 13

so l=2w-3 and given area=14
so area of rectangle is 1*w=14
now u have two equations
from two equations u will find l and w

Answer 14

\[1*w =14\]
\[\frac{ 14 }{ 1}=w ?\]

Answer 15

yes now substitute w in the first equation

Answer 16

\[l=2\left( 14 \right)-3\]
\[l= 28 -3\]
\[l= 25\] ?

Answer 17

or u can do like this 1*w=14
2*7=14 here l is 2 and w is 7
now subsitute 2 and 7 in first equation
if left hand side is equal to right hand side the values of l and w is 2 and 7

Answer 18

value of w is 14/l but u substituted on 14 so its wrong

Answer 19

its 14/L not 14/1