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write the equation in standard form and identify the conic 2y^2 - 32x + 20y + 50 = 0
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\[2y^2 - 32x + 20y + 50 = 0\]
first thing i would do is divide all by 2
then you can write it in standard form by completing the square on the y is it clear what this conic is, and what the standard form looks like?
that's what I did but once I completed the square, I got a negative value on the opposite side of the = sign @satellite73
Best if you'd please show your work. Obtaining a negative sign on the right side of your equation after you've "completed the square" for y^2-10y (but have not yet tackled the x-terms) is no indication of error. Keep going, and, again, please share the work YOU do.
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