Mark, Taylor, & Brian's ages are consecutive whole numbers. Mark is the youngest, and Brian is the oldest. The sum of their ages is 111. How old is Taylor?
A) 34 years old
B) 35 years old
C) 36 years old
D) 37 years old
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OpenStudy (photon336):
consecutive means one after the other.
\[Mark = n\]
\[Taylor, n+1\]
\[Brian, n+2\]
now the SUM = addition. just solve for n
\[n+(n+1)+(n+2) = 3n+3 = 111\]
OpenStudy (photon336):
@jurynee so what's n or mark's age?
OpenStudy (jurynee):
im trying to solve it out
OpenStudy (jurynee):
would it be 6
OpenStudy (photon336):
so we've got 3n+3 = 111
we need to get 3n by itself
we can do this by subtracting 3 from both sides first
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OpenStudy (jurynee):
nvm
OpenStudy (photon336):
\[3n = 108 \]
so what's n now marks age?
OpenStudy (jurynee):
36
OpenStudy (photon336):
now what's 36+37+38?
OpenStudy (jurynee):
111
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OpenStudy (jurynee):
i got it wrong it was 37
OpenStudy (photon336):
it asked for taylor's age..
mark is 36
so taylor would be 37
and the other guy 38