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The method used to factor trinomials of the form ax^2+bx+c can also be used to factor binomials of the form px^2+qx by realizing that, in this case, _____. a. a=0 b. b=0 c. c=0 d. x=0
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hint: in the polynomial \(px^2+qx\), the costant term is missing
so it is C ?
yes!
I thought that's what it was but I wasn't quite sure
Thank you!
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