Question

The zeros of the polynomial are the same as the roots of the equation:
1/(4p) (x - h)^2 +k = 0

Multiply the equation by 4p. Explain how adding (x – h)2 to the 3 values of k verifies the number of zeros of the polynomial.

Answer 1

HI!!

Answer 2

i assume that the variable here is \(x\) right?

Answer 3

so it you multiply by \(4p\) it ends up next to the \(k\) giving you \[(x-h)^2+4pk=0\]

Answer 4

Thanks, I've been asking this question all day!