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Which equation is the equation of a 10cm radius circle with it's center at (3, -6)
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\((x-h)^2+(y-k)^2=r^2\) H is the x value of the coordinate, K the y value, and R = radius
so(X - 3)^2 + (y - -6)^2 = r^2
but the two negatives would turn into a positive
Close (x-3)^2 is correct (y - - 6)^2 should become (y + 6)^2
And for the r^2, you would but 10^2 = ?
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20
no 10^2 = 10 * 10 not 10 * 2
oh sorry 100
Ok so the final answer is: \((x-3)^2+(y+6)^2=100\)
Tank you for your help!!
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You're welcome :)
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