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Geometry 75 Online
OpenStudy (clueless):

Can someone PLEASE help me with these 2 questions? I really need to pass all my quizzes tonight so I can go on my senior trip tomorrow. I'll fan and give anyone a medal if they can help me. I just need assistance figuring these out, everything I've tried is wrong and I'm not sure what else to do. Question 1 The figure shows an aerial view of a playground. If David runs around the field three times, he covers a distance of ____ yards. Question 2 The figure shown is formed by the arcs joining the midpoints of the four sides of a square with a side length of 15 centimeters. The area of the shape is ____ square centimeters.

OpenStudy (clueless):

Figures 1 and 2

OpenStudy (cinnamonbun):

find the circumference of the circle and perimeter of triangle, multiply both by three, and subtract the sum of the perimeter of the triangle by the sum of the circumference of the triangle Pretty sure that's how you solve the first one

OpenStudy (clueless):

would the radius of the circle be the 35 then?

OpenStudy (cinnamonbun):

yes.

OpenStudy (clueless):

so is the circumference 219.8 because thats what I keep getting. and I got 92.5 for the perimeter of the triangle does that seem correct?

OpenStudy (clueless):

@jim_thompson5910 I know you're probably busy but if you have a second do you think you could help me with either of these? I just need to figure out one of them to pass my quiz. Thank you for your time either way and I'm sorry for bothering you again

jimthompson5910 (jim_thompson5910):

Sorry I can't help with quizzes, tests, exams, etc I can only help with homework problems.

OpenStudy (clueless):

okay I understand. Thank you though!

jimthompson5910 (jim_thompson5910):

I'm sure you'll do fine. Just be confident and you'll do great. Good luck.

OpenStudy (clueless):

it's actually my PLATO class so I've taken this quiz like 500 times and I just cant figure out these problems. theres not even any similar ones in the tutorial i have to get 4/5 questions but I can only get 3/5 but i'm sure its stupidly simple and ill get it after I'm past the deadline to go on my trip haha

jimthompson5910 (jim_thompson5910):

`so is the circumference 219.8` yes C = 2*pi*r C = 2*3.14*35 C = 219.8 However don't want the full circle. We just want the piece of the circle that corresponds to the 280 degrees (recall that a full circle is 360 degrees) what we do is multiply (280/360) by the circumference (280/360)*219.8 = ???

OpenStudy (clueless):

170.95?

jimthompson5910 (jim_thompson5910):

170.955555555556 which rounds to 170.96

jimthompson5910 (jim_thompson5910):

the distance along the curved portion is approx 170.96 yards

jimthompson5910 (jim_thompson5910):

the straight portion is given to be 45 yards the total perimeter is therefore 170.96+45 = 215.96 if he ran around 3 times, then just triple the perimeter to get his total distance

OpenStudy (clueless):

647.88?

jimthompson5910 (jim_thompson5910):

yes, that's the approx answer

OpenStudy (clueless):

thank you so much. I honestly can't begin to tell you how much of lifesaver you are

jimthompson5910 (jim_thompson5910):

for the next problem, you'll need to find the area of the square, the area of each quarter circle subtract off the areas of the quarter circles from the area of the square

jimthompson5910 (jim_thompson5910):

btw, the quarter circles look to have the same radius, so they would combine to form a complete circle (4 quarter circles of the same radius glued together give a full circle) so you can say answer = (area of square) - (area of circle)

OpenStudy (clueless):

the area of the square is 225 how do I find the radius of the circles? do they have a diameter of 15 too?

jimthompson5910 (jim_thompson5910):

the side length of the square = diameter of circle radius of circle = half of the side length of the square

jimthompson5910 (jim_thompson5910):

side length of the square = 15 15/2 = 7.5 so the radius is 7.5 cm

OpenStudy (clueless):

so is it 225 - 176.63? that would be 48.37?

jimthompson5910 (jim_thompson5910):

if you use 3.14 for pi, you should get 48.375

jimthompson5910 (jim_thompson5910):

rounding that to 2 decimal places yields 48.38

jimthompson5910 (jim_thompson5910):

so the area of the shaded region is approx 48.38 square cm

OpenStudy (clueless):

Okay! Again thank you! I passed that section now! :D

jimthompson5910 (jim_thompson5910):

no problem

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