Question

Need help on #9., #12., #13., and #14.
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Need to know 1) the layout...2)the steps...3) how to do the problem...and 4) what to plug in the calculator.
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Answer 1

9. Cross multiply?

Answer 2

@CoExist2 You there?

Answer 3

Or multiply both sides by 60, either way

Answer 4

@.Sam.

Answer 5

oh thanks

Answer 6

how do i get rid of the y in#9.?

Answer 7

You don't have to, and you'll need to find the solution for y

Answer 8

\[\frac{3y-8}{12}=\frac{y}{5}\]
By cross multiplication you get
\[5(3y-8)=12y\]

Answer 9

15y-40=12y
3y-40=0
3y=40
y=40/3

Answer 10

@.Sam.
thanks.

Answer 11

can anyone help me on 12, 13, and 14#?

Answer 12

So KL is with BC and LG is with CD

Answer 13

what does that mean; how does it add up as a whole... what am i supposed to do to solve it?
@.Sam.

Answer 14

Probably
\[\frac{16}{20}=\frac{x}{9}\]

Answer 15

16 is in x, and x is BC's length and 20 is proportionate to 9, so that equation should satisfy it

Answer 16

5?

Answer 17

You'll get 7.2

Answer 18

oh okay thanks.

Answer 19

@.Sam.
Is #14. = 49?

Answer 20

For #13 no not similar

Answer 21

Is #14. = 49?
@.Sam.

Answer 22

Where did you get 49?

Answer 23

57-48=9

Answer 24

You can't do that

Answer 25

?

Answer 26

If you want it simple, 48 multiplied by what to get 57?

Answer 27

And if you divide 57 by 48 you'll get 1.1875

Answer 28

Using this number, 1.1875, and the number 40, multiplying together, you will get x, 47.5

Answer 29

oh okay thank you. this makes more sense.

Answer 30

It does, the numbers they're connected