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OpenStudy (sylph):
What does x=, according to this function?
OpenStudy (sylph):
Do you need help finding x as well?
OpenStudy (yananeedshelp):
yes
OpenStudy (sadlalkdja12111312):
y - 6 = (2/3)x + 6 - 6
y - 6 = (2/3)x
OpenStudy (sadlalkdja12111312):
(3/2)(y - 6) = (3/2)(2/3)x
(3/2)y - 18/2 = x
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OpenStudy (sadlalkdja12111312):
x = (3/2)y - 9
OpenStudy (sadlalkdja12111312):
y = (3/2)x - 9 - - > This is the inverse of y = (2/3)x + 6
OpenStudy (sylph):
-_-
OpenStudy (sylph):
Okay let's go through this step by step so you understand it better.
OpenStudy (yananeedshelp):
ok
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OpenStudy (sylph):
Move the y to the end \[\frac{ 2x }{ 3}-6=y\]
OpenStudy (sylph):
That isolated x to the lefthand side, which is where we want it in the end. Now isolate the terms with x to the lefthand side as well/
\[\frac{ 2x }{ 3 }-6=y\] You do this by adding six to both sides, so... \[\frac{ 2x }{3}-6+6=y+6\]\[-6+6=0\] \[\frac{ 2x }{ 3 }=y+6\] Multiply both sides by 3/2
\[x=\frac{ 3y }{ 2 }+9\]
OpenStudy (yananeedshelp):
y=3x/2+9
OpenStudy (sylph):
Oops I meant 6, not 9
OpenStudy (sylph):
That would wind up being \[\frac{ 3(y+6) }{ 2 }\]
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OpenStudy (sylph):
I accidentally left the 6 off of the fraction, sorry.