Question

What is the equation of the line that passes through (1, 3) and (-2, -3)?

Answer 1

@mathmate

Answer 2

There is a cumbersome formula that allows you to put in the four numbers somewhere in the formula and get the equation instantly.
But most people do it in two simple steps:
Assume P1(1,3),P2(-2,-3)
1. find the slope of the line using \(slope, m=\Large \frac{y_2-y_1}{x_2-x_1}\)
2. use the point slope form of the equation of a line:
\(\large (y-y_1)=m(x-x_1)\)
Simplify or beautify as necessary.

Answer 3

Example:
line between P1(1,2), P2(5,4)
m=(4-2)/(5-1)=2/4=(1/2)
equation of line
(y-y1)=m(x-x1)
y-2=(1/2)(x-1)
y=(1/2)x -1/2+2
y=(1/2)x+ 3/2 ...........equation of line passing through P1(1,2), P2(5,4)

Answer 4

thanks

Answer 5

You're welcome! :)