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Algebra 21 Online
OpenStudy (slaykyana):

What is the equation of the following graph in vertex form? I'm really lost

OpenStudy (slaykyana):

OpenStudy (welshfella):

general form for the vertex form 0f a parabola ids y = a(x - b)^2 + c where (b,c) are the coordinates of the vertex and a is some number

OpenStudy (welshfella):

Here (b , c) = (-1,0)

OpenStudy (welshfella):

so plug in these 2 values into the general form and what do you get?

OpenStudy (welshfella):

just replace b by -1 and c by 0

OpenStudy (slaykyana):

I got y=a(x+1)^2+0

OpenStudy (welshfella):

correct! we can forget about the 0 of course and write:- y = a(x + 1)^2 now the graph passes though the y axis at the point (0 , 1) so we can find the value of a by replacing the x and y by 0 and 1 in the above equation and solve for a. can you do that?

OpenStudy (slaykyana):

I'll try working that out now

OpenStudy (slaykyana):

would it just be a=1 ?

OpenStudy (welshfella):

yes so the equation is simply y = (x + 1)^2

OpenStudy (slaykyana):

Thank you so much! I understand it a lot better now

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