Mathematics
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OpenStudy (kiki99):
What is the exact value of x in the exponential equation 25.3 + e7x = 97.3?
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OpenStudy (kiki99):
@jabez177
OpenStudy (kiki99):
e^7x*
OpenStudy (alekos):
start by subtracting 25.3 from both sides
OpenStudy (alekos):
what do you get?
OpenStudy (kiki99):
e^7x+72
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OpenStudy (alekos):
No, e^7x = 72 correct?
OpenStudy (kiki99):
oh ok
OpenStudy (kiki99):
whats next
OpenStudy (alekos):
Now take the natural log of both sides
OpenStudy (kiki99):
i forgot how to do that
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OpenStudy (alekos):
Just take the Natural Log of both sides......
Lne^7x = Ln72 OK?
OpenStudy (kiki99):
how do i put the e in the calculator
OpenStudy (kiki99):
it give me error
OpenStudy (alekos):
Not yet, you're jumping the gun.
You have to use one of the log rules on the LHS
Ln(a^b) = bLna
OpenStudy (kiki99):
im lost i dont remember learning that last part. i dont know what im doing
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OpenStudy (alekos):
How about this
Log(a^b) = b Loga
OpenStudy (kiki99):
x = ln 72 − 7
x=In10.3/7
x=In72/7
x=In72/In7
are the choices
OpenStudy (alekos):
Yes, its definitely one of those choices.
OpenStudy (alekos):
LHS = Ln(e^7x) = ?
OpenStudy (alekos):
use what i've given you
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OpenStudy (kiki99):
okay hold on
OpenStudy (kiki99):
I Dont Know What to do.
OpenStudy (kiki99):
i need to find the value of x not solve the equation
OpenStudy (alekos):
If Ln(a^b) = bLna then what does Ln(e^7x) = ?
OpenStudy (alekos):
In order to find the value of x you first need to re-arrange the equation to make x the subject
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OpenStudy (alekos):
Goodnight